Day 23 Complete
This commit is contained in:
parent
99e36b8912
commit
54a91e53c7
@ -6,6 +6,7 @@ import (
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"strings"
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"strings"
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"time"
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"time"
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"github.com/fatih/color"
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termbox "github.com/nsf/termbox-go"
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termbox "github.com/nsf/termbox-go"
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"../../"
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"../../"
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@ -18,9 +19,10 @@ var regs = map[string]int{
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"d": 0,
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"d": 0,
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}
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}
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var instructions []string
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var instructions, lastInst []string
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var curr int
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var curr, cursor int
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var pause bool
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var pause, step, skip bool
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var breakpoints []int
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func main() {
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func main() {
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var debug bool
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var debug bool
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@ -54,70 +56,107 @@ func main() {
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var ins []string
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var ins []string
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for curr < len(instructions) || done {
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for curr < len(instructions) || done {
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if debug {
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if debug {
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lastInst := ins
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lastInst = ins
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// print state and wait for user to step
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PrintState()
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fmt.Println("Last Instruction:", lastInst)
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//PrintInstructionState()
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fmt.Println("(q): quit (space): pause/unpause")
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ev := <-eventChan
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if ev.Type == termbox.EventKey {
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if ev.Key == termbox.KeySpace {
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pause = !pause
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}
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if ev.Ch == 'q' {
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break
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}
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}
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}
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}
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ins = strings.Fields(instructions[curr])
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ins = strings.Fields(instructions[curr])
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curr++
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if len(ins) == 0 {
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break
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}
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// Optimize multiplication
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// Optimize multiplication
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/*
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/*
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// TODO:
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> cpy b c
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> cpy b c
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inc a
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inc a
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dec c
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dec c
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jnz c -2
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jnz c -2
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dec d
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dec d
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jnz d -5
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jnz d -5
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== mlt b d a
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== add (b * d) to a
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and curr += 5
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set c & d to 0
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curr += 5
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*/
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*/
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if ins[0] == "cpy" {
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if ins[0] == "cpy" {
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if len(instructions) >= curr+6 {
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if strings.HasPrefix(instructions[curr+1], "inc") && strings.HasPrefix(instructions[curr+2], "dec") && strings.HasPrefix(instructions[curr+3], "jnz") && strings.HasPrefix(instructions[curr+4], "dec") && strings.HasPrefix(instructions[curr+5], "jnz") {
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allGood := true
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// The right instruction set, make sure the arguments match up
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ins1 := strings.Fields(instructions[curr+1])
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ins1 := strings.Fields(instructions[curr+1])
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ins2 := strings.Fields(instructions[curr+2])
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ins2 := strings.Fields(instructions[curr+2])
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ins3 := strings.Fields(instructions[curr+3])
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ins3 := strings.Fields(instructions[curr+3])
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ins4 := strings.Fields(instructions[curr+4])
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ins4 := strings.Fields(instructions[curr+4])
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ins5 := strings.Fields(instructions[curr+5])
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ins5 := strings.Fields(instructions[curr+5])
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// Make sure all "c"s are correct
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if ins1[0] == "inc" && ins2[0] == "dec" && ins3[0] == "jnz" && ins4[0] == "dec" && ins5[0] == "jnz" {
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if ins[2] != ins2[1] && ins[2] != ins3[1] {
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allGood := true
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if allGood {
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// Do the multiplication
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// ins[1] * ins4[1]
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// add that value to ins1[1]
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// set ins[2] to 0
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// set ins4[1] to 0
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// Then add 5 to the pc
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src1 := ins[1]
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src2 := ins4[1]
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dst := ins1[1]
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if _, ok := regs[dst]; !ok {
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// Invalid destination register
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allGood = false
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}
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if _, ok := regs[src1]; !ok {
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// Invalid source register
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allGood = false
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}
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if _, ok := regs[src2]; !ok {
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allGood = false
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allGood = false
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}
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}
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if allGood {
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if allGood {
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// Make sure all "b"s are correct
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regs[dst] += (regs[src1] * regs[src2])
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if ins[1] == ins1[1] || ins[1] == ins2[1] || ins[1] == ins4[1] {
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curr += 6
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allGood = false
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skip = true
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}
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}
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if allGood {
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// Make sure all "d"s are correct
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if (ins[1] == ins4[1] || ins[2] == ins4[1]) || ins4[1] != ins5[1] {
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allGood = false
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}
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}
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if allGood {
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// Go ahead and change the instruction
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ins = []string{"mult", ins[1], ins4[1], ins1[1]}
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curr += 5
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}
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}
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}
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}
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}
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}
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}
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}
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if debug {
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if isBreakpoint(curr + 1) {
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pause = true
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step = false
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}
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for pause && !step {
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// print state and wait for user to step
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PrintState()
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fmt.Println("Last Instruction:", lastInst)
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PrintInstructionState()
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fmt.Println("(q): quit (space): pause/unpause (s): step (b): toggle breakpoint")
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ev := <-eventChan
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if ev.Type == termbox.EventKey {
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switch {
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case ev.Key == termbox.KeySpace:
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pause = !pause
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case ev.Ch == 'q':
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done = true
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case ev.Ch == 'b':
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toggleBreakpoint(cursor)
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case ev.Ch == 's':
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step = true
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case ev.Key == termbox.KeyArrowUp:
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if cursor > 0 {
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cursor--
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}
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case ev.Key == termbox.KeyArrowDown:
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if cursor < len(instructions)-1 {
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cursor++
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}
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}
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}
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}
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step = false
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}
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if done {
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// User hit 'q'
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break
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}
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if skip {
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skip = false
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continue
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}
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curr++
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switch ins[0] {
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switch ins[0] {
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case "jnz":
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case "jnz":
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// If we have a jnz c -2 it could be moving all of c into another register
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// If we have a jnz c -2 it could be moving all of c into another register
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@ -211,6 +250,8 @@ func main() {
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}
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}
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}
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}
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PrintState()
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PrintState()
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fmt.Println("Press any key to exit")
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termbox.PollEvent()
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}
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}
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// Fancy State Printing
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// Fancy State Printing
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@ -233,8 +274,18 @@ func PrintInstructionState() {
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} else {
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} else {
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fmt.Print(" ")
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fmt.Print(" ")
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}
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}
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if isBreakpoint(pi) {
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fmt.Print("B")
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} else {
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fmt.Print(" ")
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}
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if cursor == pi {
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cursor := color.New(color.FgBlack).Add(color.BgWhite)
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cursor.Println(instructions[pi])
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} else {
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fmt.Println(instructions[pi])
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fmt.Println(instructions[pi])
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}
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}
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}
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fmt.Println(instructions[curr])
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fmt.Println(instructions[curr])
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}
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}
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@ -252,3 +303,22 @@ func sendNoneEvent(e chan termbox.Event) {
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}
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}
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}
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}
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}
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}
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func toggleBreakpoint(pos int) {
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for i := 0; i < len(breakpoints); i++ {
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if breakpoints[i] == pos {
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breakpoints = append(breakpoints[:i], breakpoints[i+1:]...)
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return
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}
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}
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breakpoints = append(breakpoints, pos)
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}
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func isBreakpoint(pos int) bool {
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for i := 0; i < len(breakpoints); i++ {
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if breakpoints[i] == pos {
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return true
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}
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}
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return false
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}
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93
2016/day23/problem
Normal file
93
2016/day23/problem
Normal file
@ -0,0 +1,93 @@
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Advent of Code
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--- Day 23: Safe Cracking ---
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This is one of the top floors of the nicest tower in EBHQ. The Easter Bunny's private office is here, complete with
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a safe hidden behind a painting, and who wouldn't hide a star in a safe behind a painting?
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The safe has a digital screen and keypad for code entry. A sticky note attached to the safe has a password hint on
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it: "eggs". The painting is of a large rabbit coloring some eggs. You see 7.
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When you go to type the code, though, nothing appears on the display; instead, the keypad comes apart in your
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hands, apparently having been smashed. Behind it is some kind of socket - one that matches a connector in your
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prototype computer! You pull apart the smashed keypad and extract the logic circuit, plug it into your computer,
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and plug your computer into the safe.
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Now, you just need to figure out what output the keypad would have sent to the safe. You extract the assembunny
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code from the logic chip (your puzzle input).
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The code looks like it uses almost the same architecture and instruction set that the monorail computer used! You
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should be able to use the same assembunny interpreter for this as you did there, but with one new instruction:
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tgl x toggles the instruction x away (pointing at instructions like jnz does: positive means forward; negative
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means backward):
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• For one-argument instructions, inc becomes dec, and all other one-argument instructions become inc.
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• For two-argument instructions, jnz becomes cpy, and all other two-instructions become jnz.
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• The arguments of a toggled instruction are not affected.
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• If an attempt is made to toggle an instruction outside the program, nothing happens.
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• If toggling produces an invalid instruction (like cpy 1 2) and an attempt is later made to execute that
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instruction, skip it instead.
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• If tgl toggles itself (for example, if a is 0, tgl a would target itself and become inc a), the resulting
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instruction is not executed until the next time it is reached.
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For example, given this program:
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cpy 2 a
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tgl a
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tgl a
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tgl a
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cpy 1 a
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dec a
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dec a
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• cpy 2 a initializes register a to 2.
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• The first tgl a toggles an instruction a (2) away from it, which changes the third tgl a into inc a.
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• The second tgl a also modifies an instruction 2 away from it, which changes the cpy 1 a into jnz 1 a.
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• The fourth line, which is now inc a, increments a to 3.
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• Finally, the fifth line, which is now jnz 1 a, jumps a (3) instructions ahead, skipping the dec a instructions.
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In this example, the final value in register a is 3.
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The rest of the electronics seem to place the keypad entry (the number of eggs, 7) in register a, run the code, and
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then send the value left in register a to the safe.
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What value should be sent to the safe?
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Your puzzle answer was ________.
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--- Part Two ---
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The safe doesn't open, but it does make several angry noises to express its frustration.
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You're quite sure your logic is working correctly, so the only other thing is... you check the painting again. As
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it turns out, colored eggs are still eggs. Now you count 12.
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As you run the program with this new input, the prototype computer begins to overheat. You wonder what's taking so
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long, and whether the lack of any instruction more powerful than "add one" has anything to do with it. Don't
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bunnies usually multiply?
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Anyway, what value should actually be sent to the safe?
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Your puzzle answer was ____________.
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References
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Visible links
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. http://adventofcode.com/
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. http://adventofcode.com/2016/about
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. http://adventofcode.com/2016/support
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. http://adventofcode.com/2016/events
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. http://adventofcode.com/2016/settings
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. http://adventofcode.com/2016/auth/logout
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. http://adventofcode.com/2016
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. http://adventofcode.com/2016
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. http://adventofcode.com/2016/leaderboard
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. http://adventofcode.com/2016/stats
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. http://adventofcode.com/2016/sponsors
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. http://adventofcode.com/2016/sponsors
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. http://adventofcode.com/2016/day/11
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. http://adventofcode.com/2016/day/12
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. http://adventofcode.com/2016/day/12
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. http://adventofcode.com/2016
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. http://adventofcode.com/2016/day/23/input
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@ -1,7 +0,0 @@
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cpy 2 a
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tgl a
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tgl a
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tgl a
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cpy 1 a
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dec a
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dec a
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Loading…
Reference in New Issue
Block a user