Reflowed problems and added solutions

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2018-03-15 11:24:23 -05:00
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@@ -2,31 +2,40 @@ Advent of Code
--- Day 12: Leonardo's Monorail ---
You finally reach the top floor of this building: a garden with a slanted glass ceiling. Looks like there are no more
stars to be had.
You finally reach the top floor of this building: a garden with a slanted
glass ceiling. Looks like there are no more stars to be had.
While sitting on a nearby bench amidst some tiger lilies, you manage to decrypt some of the files you extracted from
the servers downstairs.
While sitting on a nearby bench amidst some tiger lilies, you manage to
decrypt some of the files you extracted from the servers downstairs.
According to these documents, Easter Bunny HQ isn't just this building - it's a collection of buildings in the nearby
area. They're all connected by a local monorail, and there's another building not far from here! Unfortunately, being
night, the monorail is currently not operating.
According to these documents, Easter Bunny HQ isn't just this building -
it's a collection of buildings in the nearby area. They're all connected by
a local monorail, and there's another building not far from here!
Unfortunately, being night, the monorail is currently not operating.
You remotely connect to the monorail control systems and discover that the boot sequence expects a password. The
password-checking logic (your puzzle input) is easy to extract, but the code it uses is strange: it's assembunny code
designed for the new computer you just assembled. You'll have to execute the code and get the password.
You remotely connect to the monorail control systems and discover that the
boot sequence expects a password. The password-checking logic (your puzzle
input) is easy to extract, but the code it uses is strange: it's assembunny
code designed for the new computer you just assembled. You'll have to
execute the code and get the password.
The assembunny code you've extracted operates on four registers (a, b, c, and d) that start at 0 and can hold any
integer. However, it seems to make use of only a few instructions:
The assembunny code you've extracted operates on four registers (a, b, c,
and d) that start at 0 and can hold any integer. However, it seems to make
use of only a few instructions:
 cpy x y copies x (either an integer or the value of a register) into
register y.
 cpy x y copies x (either an integer or the value of a register) into register y.
 inc x increases the value of register x by one.
 dec x decreases the value of register x by one.
 jnz x y jumps to an instruction y away (positive means forward; negative means backward), but only if x is not
zero.
The jnz instruction moves relative to itself: an offset of -1 would continue at the previous instruction, while an
offset of 2 would skip over the next instruction.
 dec x decreases the value of register x by one.
 jnz x y jumps to an instruction y away (positive means forward; negative
means backward), but only if x is not zero.
The jnz instruction moves relative to itself: an offset of -1 would continue
at the previous instruction, while an offset of 2 would skip over the next
instruction.
For example:
@@ -37,22 +46,26 @@ Advent of Code
jnz a 2
dec a
The above code would set register a to 41, increase its value by 2, decrease its value by 1, and then skip the last
dec a (because a is not zero, so the jnz a 2 skips it), leaving register a at 42. When you move past the last
The above code would set register a to 41, increase its value by 2, decrease
its value by 1, and then skip the last dec a (because a is not zero, so the
jnz a 2 skips it), leaving register a at 42. When you move past the last
instruction, the program halts.
After executing the assembunny code in your puzzle input, what value is left in register a?
After executing the assembunny code in your puzzle input, what value is left
in register a?
Your puzzle answer was __________.
Your puzzle answer was 318077.
--- Part Two ---
As you head down the fire escape to the monorail, you notice it didn't start; register c needs to be initialized to
the position of the ignition key.
As you head down the fire escape to the monorail, you notice it didn't
start; register c needs to be initialized to the position of the ignition
key.
If you instead initialize register c to be 1, what value is now left in register a?
If you instead initialize register c to be 1, what value is now left in
register a?
Your puzzle answer was ___________.
Your puzzle answer was 9227731.
References