2018 day 12 done
This commit is contained in:
parent
c7af2e1eb7
commit
18d07e81db
@ -7,136 +7,177 @@ import (
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"strings"
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)
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var row map[int]bool
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var transitions []*Transition
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const (
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MaxInt = int(^uint(0) >> 1)
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MinInt = -MaxInt - 1
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)
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var lastState string
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var garden *Garden
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func main() {
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inp := StdinToStringSlice()
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BuildRow(inp[0])
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garden = NewGarden(strings.Trim(inp[0], "intalsae: "), 0)
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for _, v := range inp[2:] {
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transitions = append(transitions, NewTransition(v))
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garden.transitions = append(garden.transitions, NewTransition(v))
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}
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fmt.Print("St: ")
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PrintState()
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for i := 0; i < 20; i++ {
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Tick()
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fmt.Printf("%2d: ", i)
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PrintState()
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generations := 50000000000
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var i int
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for i = 0; i < generations; i++ {
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lastState = garden.string()
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garden = garden.tick()
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if garden.string() == lastState {
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i++
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break
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}
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}
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fmt.Println("Total:", GetSum())
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garden.shiftPots(generations - i)
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fmt.Println(garden.sum())
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}
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func Tick() {
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m := make(map[int]bool)
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lowest, highest := 0, 0
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for i := range row {
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if i < lowest {
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lowest = i
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}
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if i > highest {
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highest = i
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/**
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* A Garden
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*/
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type Garden struct {
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pots []*Pot
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transitions []*Transition
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}
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func NewGarden(inp string, start int) *Garden {
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g := &Garden{}
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for k, v := range inp {
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p := &Pot{
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id: k + start,
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value: rb(v),
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}
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g.pots = append(g.pots, p)
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}
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for i := lowest - 2; i <= highest+2; i++ {
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m[i] = GetNextValue(i)
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}
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lowest, highest = 0, 0
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for k := range m {
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if k < lowest && m[k] {
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lowest = k
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}
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if k > highest && m[k] {
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highest = k
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}
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}
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row = make(map[int]bool)
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for i := lowest; i <= highest; i++ {
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row[i] = m[i]
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return g
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}
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func (g *Garden) shiftPots(val int) {
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for i := range g.pots {
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g.pots[i].id = g.pots[i].id + val
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}
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}
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func GetSum() int {
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var ret int
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lowest, highest := 0, 0
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for i := range row {
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if i < lowest {
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lowest = i
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}
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if i > highest {
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highest = i
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}
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}
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for i := lowest; i <= highest; i++ {
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if row[i] {
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ret += i
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func (g *Garden) sum() int64 {
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var ret int64
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st, ed := g.getStartIndex(), g.getEndIndex()
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for i := st; i <= ed; i++ {
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if g.getPot(i).value {
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ret += int64(i)
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}
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}
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return ret
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}
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func BuildRow(inp string) {
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inp = strings.Split(inp, ": ")[1]
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row = make(map[int]bool)
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for i, v := range inp {
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row[i] = rb(v)
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func (g *Garden) tick() *Garden {
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earliest, latest := g.getStartIndex(), g.getEndIndex()
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st := earliest - 2
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ed := latest + 2
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ret := &Garden{
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transitions: g.transitions,
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}
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for i := st; i <= ed; i++ {
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next := g.getNextStateForPot(i)
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if next {
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ret.pots = append(ret.pots, &Pot{
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id: i,
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value: next,
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})
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}
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}
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return ret
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}
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func GetIdxValue(idx int) byte {
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func (g *Garden) getNextStateForPot(id int) bool {
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var ret byte
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for i := idx + 2; i >= idx-2; i-- {
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for i := id - 2; i <= id+2; i++ {
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ret = ret << 1
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if row[i] {
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if g.getPot(i).value {
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ret = ret | 1
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}
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}
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return ret
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}
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func GetNextValue(idx int) bool {
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idxVal := GetIdxValue(idx)
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for _, v := range transitions {
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if v.GetValue() == idxVal {
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for _, v := range g.transitions {
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if v.GetValue() == ret {
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return v.next
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}
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}
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return false
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return false //g.getPot(id).value
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}
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func GetValueString(b byte) string {
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func (g *Garden) substring(st, ed int) string {
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var ret string
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for i := 0; i < 5; i++ {
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if (b & 1) == 1 {
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ret = ret + "#"
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} else {
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ret = ret + "."
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}
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b = b >> 1
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for i := st; i <= ed; i++ {
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ret += g.getPot(i).string()
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}
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return ret
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}
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func PrintState() {
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lowest, highest := -2, 30
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for i := range row {
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if i < lowest {
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lowest = i
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}
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if i > highest {
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highest = i
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}
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func (g *Garden) string() string {
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var ret string
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for i := g.getStartIndex(); i <= g.getEndIndex(); i++ {
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ret += g.getPot(i).string()
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}
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fmt.Print("(", lowest, ") ")
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for i := lowest; i <= highest; i++ {
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if row[i] {
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fmt.Print("#")
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} else {
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fmt.Print(".")
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}
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}
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fmt.Println(" (", highest, ") ")
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return ret
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}
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func (g *Garden) transitionStrings() string {
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var ret string
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for _, v := range g.transitions {
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ret = ret + v.string() + "\n"
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}
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return ret
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}
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func (g *Garden) getStartIndex() int {
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min := MaxInt
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for _, v := range g.pots {
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if v.id < min {
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min = v.id
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}
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}
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return min
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}
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func (g *Garden) getEndIndex() int {
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max := MinInt
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for _, v := range g.pots {
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if v.id > max {
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max = v.id
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}
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}
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return max
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}
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func (g *Garden) getPot(idx int) *Pot {
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for _, v := range g.pots {
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if v.id == idx {
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return v
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}
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}
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return &Pot{
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id: idx,
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value: false,
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}
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}
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/**
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* A Pot
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*/
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type Pot struct {
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id int
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value bool
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}
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func (p *Pot) string() string {
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return bs(p.value)
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}
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/**
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* Transitions
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*/
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type Transition struct {
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state []bool
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next bool
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@ -146,9 +187,12 @@ func NewTransition(inp string) *Transition {
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var state []bool
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var next bool
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pts := strings.Split(inp, " => ")
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for i := len(pts[0]) - 1; i >= 0; i-- {
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for i := range pts[0] {
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state = append(state, bb(pts[0][i]))
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}
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//for i := len(pts[0]) - 1; i >= 0; i-- {
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// state = append(state, bb(pts[0][i]))
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//}
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next = bb(pts[1][0])
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t := &Transition{
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state: state,
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@ -157,6 +201,14 @@ func NewTransition(inp string) *Transition {
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return t
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}
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func (t *Transition) string() string {
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var ret string
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for _, v := range t.state {
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ret += bs(v)
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}
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return ret + " => " + bs(t.next)
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}
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func (t *Transition) GetValue() byte {
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var ret byte
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for _, v := range t.state {
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@ -168,6 +220,43 @@ func (t *Transition) GetValue() byte {
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return ret
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}
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/**
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* Helper Functions
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*/
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// Take a byte and return a string representation of the bits
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func byteToString(b byte) string {
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var ret string
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for i := 0; i < 8; i++ {
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if b&1 == 1 {
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ret += "#"
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} else {
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ret += "."
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}
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b = b >> 1
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}
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return ret
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}
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// Take a string representation of a bits and return the byte
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func stringToByte(n string) byte {
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var b byte
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for i := range n {
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if n[i] == '#' {
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b = b | 1
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}
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b = b << 1
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}
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return b
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}
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func bs(b bool) string {
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if b {
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return "#"
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}
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return "."
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}
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func rb(r rune) bool {
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return bb(byte(r))
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}
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123
2018/day12/problem
Normal file
123
2018/day12/problem
Normal file
@ -0,0 +1,123 @@
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Advent of Code
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--- Day 12: Subterranean Sustainability ---
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The year 518 is significantly more underground than your history books implied. Either that, or you've arrived in a vast
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cavern network under the North Pole.
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After exploring a little, you discover a long tunnel that contains a row of small pots as far as you can see to your left
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and right. A few of them contain plants - someone is trying to grow things in these geothermally-heated caves.
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The pots are numbered, with 0 in front of you. To the left, the pots are numbered -1, -2, -3, and so on; to the right, 1, 2,
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3.... Your puzzle input contains a list of pots from 0 to the right and whether they do (#) or do not (.) currently contain
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a plant, the initial state. (No other pots currently contain plants.) For example, an initial state of #..##.... indicates
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that pots 0, 3, and 4 currently contain plants.
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Your puzzle input also contains some notes you find on a nearby table: someone has been trying to figure out how these
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plants spread to nearby pots. Based on the notes, for each generation of plants, a given pot has or does not have a plant
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based on whether that pot (and the two pots on either side of it) had a plant in the last generation. These are written as
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LLCRR => N, where L are pots to the left, C is the current pot being considered, R are the pots to the right, and N is
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whether the current pot will have a plant in the next generation. For example:
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• A note like ..#.. => . means that a pot that contains a plant but with no plants within two pots of it will not have a
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plant in it during the next generation.
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• A note like ##.## => . means that an empty pot with two plants on each side of it will remain empty in the next
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generation.
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• A note like .##.# => # means that a pot has a plant in a given generation if, in the previous generation, there were
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plants in that pot, the one immediately to the left, and the one two pots to the right, but not in the ones immediately
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to the right and two to the left.
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It's not clear what these plants are for, but you're sure it's important, so you'd like to make sure the current
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configuration of plants is sustainable by determining what will happen after 20 generations.
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For example, given the following input:
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initial state: #..#.#..##......###...###
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...## => #
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..#.. => #
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.#... => #
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.#.#. => #
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.#.## => #
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.##.. => #
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.#### => #
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#.#.# => #
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#.### => #
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##.#. => #
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##.## => #
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###.. => #
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###.# => #
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####. => #
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For brevity, in this example, only the combinations which do produce a plant are listed. (Your input includes all possible
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combinations.) Then, the next 20 generations will look like this:
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1 2 3
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0 0 0 0
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0: ...#..#.#..##......###...###...........
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1: ...#...#....#.....#..#..#..#...........
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2: ...##..##...##....#..#..#..##..........
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3: ..#.#...#..#.#....#..#..#...#..........
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4: ...#.#..#...#.#...#..#..##..##.........
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5: ....#...##...#.#..#..#...#...#.........
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6: ....##.#.#....#...#..##..##..##........
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7: ...#..###.#...##..#...#...#...#........
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8: ...#....##.#.#.#..##..##..##..##.......
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9: ...##..#..#####....#...#...#...#.......
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10: ..#.#..#...#.##....##..##..##..##......
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11: ...#...##...#.#...#.#...#...#...#......
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12: ...##.#.#....#.#...#.#..##..##..##.....
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13: ..#..###.#....#.#...#....#...#...#.....
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14: ..#....##.#....#.#..##...##..##..##....
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15: ..##..#..#.#....#....#..#.#...#...#....
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16: .#.#..#...#.#...##...#...#.#..##..##...
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17: ..#...##...#.#.#.#...##...#....#...#...
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18: ..##.#.#....#####.#.#.#...##...##..##..
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19: .#..###.#..#.#.#######.#.#.#..#.#...#..
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20: .#....##....#####...#######....#.#..##.
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The generation is shown along the left, where 0 is the initial state. The pot numbers are shown along the top, where 0
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labels the center pot, negative-numbered pots extend to the left, and positive pots extend toward the right. Remember, the
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initial state begins at pot 0, which is not the leftmost pot used in this example.
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After one generation, only seven plants remain. The one in pot 0 matched the rule looking for ..#.., the one in pot 4
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matched the rule looking for .#.#., pot 9 matched .##.., and so on.
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In this example, after 20 generations, the pots shown as # contain plants, the furthest left of which is pot -2, and the
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furthest right of which is pot 34. Adding up all the numbers of plant-containing pots after the 20th generation produces
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325.
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After 20 generations, what is the sum of the numbers of all pots which contain a plant?
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Your puzzle answer was 2281.
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--- Part Two ---
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You realize that 20 generations aren't enough. After all, these plants will need to last another 1500 years to even reach
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your timeline, not to mention your future.
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After fifty billion (50000000000) generations, what is the sum of the numbers of all pots which contain a plant?
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Your puzzle answer was 2250000000120.
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Both parts of this puzzle are complete! They provide two gold stars: **
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References
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Visible links
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. https://adventofcode.com/
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. https://adventofcode.com/2018/about
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. https://adventofcode.com/2018/events
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. https://adventofcode.com/2018/settings
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. https://adventofcode.com/2018/auth/logout
|
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. Advent of Code Supporter
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https://adventofcode.com/2018/support
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. https://adventofcode.com/2018
|
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. https://adventofcode.com/2018
|
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. https://adventofcode.com/2018/support
|
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. https://adventofcode.com/2018/sponsors
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. https://adventofcode.com/2018/leaderboard
|
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. https://adventofcode.com/2018/stats
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. https://adventofcode.com/2018/sponsors
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. https://adventofcode.com/2018
|
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. https://adventofcode.com/2018/day/12/input
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