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leap

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# Leap
Write a program that will take a year and report if it is a leap year.
The tricky thing here is that a leap year occurs:
```plain
on every year that is evenly divisible by 4
except every year that is evenly divisible by 100
unless the year is also evenly divisible by 400
```
For example, 1997 is not a leap year, but 1996 is. 1900 is not a leap
year, but 2000 is.
If your language provides a method in the standard library that does
this look-up, pretend it doesn't exist and implement it yourself.
## Notes
For a delightful, four minute explanation of the whole leap year
phenomenon, go watch [this youtube video][video].
[video]: http://www.youtube.com/watch?v=xX96xng7sAE
Check out [Exercism
Help](http://help.exercism.io/getting-started-with-haskell.html) for
instructions to get started writing Haskell.
## Running Tests
Use `runhaskell` (included in the Haskell Platform) to compile and run your
Haskell code.
$ runhaskell -Wall bob_test.hs
## Source
JavaRanch Cattle Drive, exercise 3 [view source](http://www.javaranch.com/leap.jsp)

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import Test.HUnit (Assertion, (@=?), runTestTT, Test(..), Counts(..))
import System.Exit (ExitCode(..), exitWith)
import LeapYear (isLeapYear)
exitProperly :: IO Counts -> IO ()
exitProperly m = do
counts <- m
exitWith $ if failures counts /= 0 || errors counts /= 0 then ExitFailure 1 else ExitSuccess
testCase :: String -> Assertion -> Test
testCase label assertion = TestLabel label (TestCase assertion)
main :: IO ()
main = exitProperly $ runTestTT $ TestList
[ TestList isLeapYearTests ]
isLeapYearTests :: [Test]
isLeapYearTests =
[ testCase "vanilla leap year" $
True @=? isLeapYear 1996
, testCase "any old year" $
False @=? isLeapYear 1997
, testCase "century" $
False @=? isLeapYear 1900
, testCase "exceptional century" $
True @=? isLeapYear 2400
]