diff --git a/2023/day15/input b/2023/day15/input new file mode 100644 index 0000000..e84ef1c --- /dev/null +++ b/2023/day15/input @@ -0,0 +1 @@ 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diff --git a/2023/day15/main.go b/2023/day15/main.go new file mode 100644 index 0000000..95b352b --- /dev/null +++ b/2023/day15/main.go @@ -0,0 +1,128 @@ +package main + +import ( + "fmt" + "strings" + + h "git.bullercodeworks.com/brian/adventofcode/helpers" +) + +func main() { + inp := h.StdinToString() + part1(inp) + fmt.Println() + part2(inp) +} + +func part1(input string) { + var res int + pts := strings.Split(input, ",") + for i := range pts { + res += hash(pts[i]) + } + fmt.Println("# Part 1") + fmt.Println(res) +} + +func part2(input string) { + var boxes []*Box + for i := 1; i <= 256; i++ { + boxes = append(boxes, &Box{num: i}) + } + for _, v := range strings.Split(input, ",") { + l := NewLens(v) + if l.focalLength == -1 { + // Remove + boxes[l.box].Remove(l) + } else { + // Add/Replace + boxes[l.box].Add(l) + } + } + var res int + for i := range boxes { + res += boxes[i].FocusingPower() + } + fmt.Println("# Part 2") + fmt.Println(res) +} + +type Box struct { + num int + lenses []*Lens +} + +func (b *Box) Add(l *Lens) { + for i := range b.lenses { + if b.lenses[i].label == l.label { + b.lenses[i] = l + return + } + } + b.lenses = append(b.lenses, l) +} +func (b *Box) Remove(l *Lens) { + for i := range b.lenses { + if b.lenses[i].label == l.label { + b.lenses = append(b.lenses[:i], b.lenses[i+1:]...) + return + } + } +} +func (b *Box) FocusingPower() int { + var res int + for i := range b.lenses { + var lensRes int + lensRes = b.num + lensRes *= i + 1 + lensRes *= b.lenses[i].focalLength + res += lensRes + } + return res +} + +type Lens struct { + label string + focalLength int + box int +} + +func NewLens(inp string) *Lens { + if strings.Contains(inp, "=") { + pts := strings.Split(inp, "=") + return &Lens{ + label: pts[0], + focalLength: h.Atoi(pts[1]), + box: hash(pts[0]), + } + } else { + lbl := strings.TrimSuffix(inp, "-") + return &Lens{ + label: lbl, + focalLength: -1, + box: hash(lbl), + } + } +} + +func hash(inp string) int { + var res int + for _, i := range inp { + res += int(i) + res *= 17 + res = res % 256 + } + return res +} + +func focusingPower(lens string, boxNum int, boxes [][]string) int { + res := boxNum + 1 + for i := 1; i <= len(boxes[boxNum]); i++ { + if boxes[boxNum][i-1] == lens { + res *= i + break + } + } + + return res +} diff --git a/2023/day15/problem b/2023/day15/problem new file mode 100644 index 0000000..018f9ad --- /dev/null +++ b/2023/day15/problem @@ -0,0 +1,296 @@ + [1]Advent of Code + + • [2][About] + • [3][Events] + • [4][Shop] + • [5][Settings] + • [6][Log Out] + + br0xen [7](AoC++) 30* + +   0.0.0.0:[8]2023 + + • [9][Calendar] + • [10][AoC++] + • [11][Sponsors] + • [12][Leaderboard] + • [13][Stats] + + Our [14]sponsors help make Advent of Code possible: + [15]Honeycomb - On call for the holidays? Honeycomb adopters are happier + and less burned out because we make your complex systems easy to + understand. + +--- Day 15: Lens Library --- + + The newly-focused parabolic reflector dish is sending all of the collected + light to a point on the side of yet another mountain - the largest + mountain on Lava Island. As you approach the mountain, you find that the + light is being collected by the wall of a large facility embedded in the + mountainside. + + You find a door under a large sign that says "Lava Production Facility" + and next to a smaller sign that says "Danger - Personal Protective + Equipment required beyond this point". + + As you step inside, you are immediately greeted by a somewhat panicked + reindeer wearing goggles and a loose-fitting [16]hard hat. The reindeer + leads you to a shelf of goggles and hard hats (you quickly find some that + fit) and then further into the facility. At one point, you pass a button + with a faint snout mark and the label "PUSH FOR HELP". No wonder you were + loaded into that [17]trebuchet so quickly! + + You pass through a final set of doors surrounded with even more warning + signs and into what must be the room that collects all of the light from + outside. As you admire the large assortment of lenses available to further + focus the light, the reindeer brings you a book titled "Initialization + Manual". + + "Hello!", the book cheerfully begins, apparently unaware of the concerned + reindeer reading over your shoulder. "This procedure will let you bring + the Lava Production Facility online - all without burning or melting + anything unintended!" + + "Before you begin, please be prepared to use the Holiday ASCII String + Helper algorithm (appendix 1A)." You turn to appendix 1A. The reindeer + leans closer with interest. + + The HASH algorithm is a way to turn any [18]string of characters into a + single number in the range 0 to 255. To run the HASH algorithm on a + string, start with a current value of 0. Then, for each character in the + string starting from the beginning: + + • Determine the [19]ASCII code for the current character of the string. + • Increase the current value by the ASCII code you just determined. + • Set the current value to itself multiplied by 17. + • Set the current value to the [20]remainder of dividing itself by 256. + + After following these steps for each character in the string in order, the + current value is the output of the HASH algorithm. + + So, to find the result of running the HASH algorithm on the string HASH: + + • The current value starts at 0. + • The first character is H; its ASCII code is 72. + • The current value increases to 72. + • The current value is multiplied by 17 to become 1224. + • The current value becomes 200 (the remainder of 1224 divided by 256). + • The next character is A; its ASCII code is 65. + • The current value increases to 265. + • The current value is multiplied by 17 to become 4505. + • The current value becomes 153 (the remainder of 4505 divided by 256). + • The next character is S; its ASCII code is 83. + • The current value increases to 236. + • The current value is multiplied by 17 to become 4012. + • The current value becomes 172 (the remainder of 4012 divided by 256). + • The next character is H; its ASCII code is 72. + • The current value increases to 244. + • The current value is multiplied by 17 to become 4148. + • The current value becomes 52 (the remainder of 4148 divided by 256). + + So, the result of running the HASH algorithm on the string HASH is 52. + + The initialization sequence (your puzzle input) is a comma-separated list + of steps to start the Lava Production Facility. Ignore newline characters + when parsing the initialization sequence. To verify that your HASH + algorithm is working, the book offers the sum of the result of running the + HASH algorithm on each step in the initialization sequence. + + For example: + + rn=1,cm-,qp=3,cm=2,qp-,pc=4,ot=9,ab=5,pc-,pc=6,ot=7 + + This initialization sequence specifies 11 individual steps; the result of + running the HASH algorithm on each of the steps is as follows: + + • rn=1 becomes 30. + • cm- becomes 253. + • qp=3 becomes 97. + • cm=2 becomes 47. + • qp- becomes 14. + • pc=4 becomes 180. + • ot=9 becomes 9. + • ab=5 becomes 197. + • pc- becomes 48. + • pc=6 becomes 214. + • ot=7 becomes 231. + + In this example, the sum of these results is 1320. Unfortunately, the + reindeer has stolen the page containing the expected verification number + and is currently running around the facility with it excitedly. + + Run the HASH algorithm on each step in the initialization sequence. What + is the sum of the results? (The initialization sequence is one long line; + be careful when copy-pasting it.) + + Your puzzle answer was 515495. + +--- Part Two --- + + You convince the reindeer to bring you the page; the page confirms that + your HASH algorithm is working. + + The book goes on to describe a series of 256 boxes numbered 0 through 255. + The boxes are arranged in a line starting from the point where light + enters the facility. The boxes have holes that allow light to pass from + one box to the next all the way down the line. + + +-----+ +-----+ +-----+ + Light | Box | | Box | ... | Box | + -----------------------------------------> + | 0 | | 1 | ... | 255 | + +-----+ +-----+ +-----+ + + Inside each box, there are several lens slots that will keep a lens + correctly positioned to focus light passing through the box. The side of + each box has a panel that opens to allow you to insert or remove lenses as + necessary. + + Along the wall running parallel to the boxes is a large library containing + lenses organized by focal length ranging from 1 through 9. The reindeer + also brings you a small handheld [21]label printer. + + The book goes on to explain how to perform each step in the initialization + sequence, a process it calls the Holiday ASCII String Helper Manual + Arrangement Procedure, or HASHMAP for short. + + Each step begins with a sequence of letters that indicate the label of the + lens on which the step operates. The result of running the HASH algorithm + on the label indicates the correct box for that step. + + The label will be immediately followed by a character that indicates the + operation to perform: either an equals sign (=) or a dash (-). + + If the operation character is a dash (-), go to the relevant box and + remove the lens with the given label if it is present in the box. Then, + move any remaining lenses as far forward in the box as they can go without + changing their order, filling any space made by removing the indicated + lens. (If no lens in that box has the given label, nothing happens.) + + If the operation character is an equals sign (=), it will be followed by a + number indicating the focal length of the lens that needs to go into the + relevant box; be sure to use the label maker to mark the lens with the + label given in the beginning of the step so you can find it later. There + are two possible situations: + + • If there is already a lens in the box with the same label, replace the + old lens with the new lens: remove the old lens and put the new lens + in its place, not moving any other lenses in the box. + • If there is not already a lens in the box with the same label, add the + lens to the box immediately behind any lenses already in the box. + Don't move any of the other lenses when you do this. If there aren't + any lenses in the box, the new lens goes all the way to the front of + the box. + + Here is the contents of every box after each step in the example + initialization sequence above: + + After "rn=1": + Box 0: [rn 1] + + After "cm-": + Box 0: [rn 1] + + After "qp=3": + Box 0: [rn 1] + Box 1: [qp 3] + + After "cm=2": + Box 0: [rn 1] [cm 2] + Box 1: [qp 3] + + After "qp-": + Box 0: [rn 1] [cm 2] + + After "pc=4": + Box 0: [rn 1] [cm 2] + Box 3: [pc 4] + + After "ot=9": + Box 0: [rn 1] [cm 2] + Box 3: [pc 4] [ot 9] + + After "ab=5": + Box 0: [rn 1] [cm 2] + Box 3: [pc 4] [ot 9] [ab 5] + + After "pc-": + Box 0: [rn 1] [cm 2] + Box 3: [ot 9] [ab 5] + + After "pc=6": + Box 0: [rn 1] [cm 2] + Box 3: [ot 9] [ab 5] [pc 6] + + After "ot=7": + Box 0: [rn 1] [cm 2] + Box 3: [ot 7] [ab 5] [pc 6] + + All 256 boxes are always present; only the boxes that contain any lenses + are shown here. Within each box, lenses are listed from front to back; + each lens is shown as its label and focal length in square brackets. + + To confirm that all of the lenses are installed correctly, add up the + focusing power of all of the lenses. The focusing power of a single lens + is the result of multiplying together: + + • One plus the box number of the lens in question. + • The slot number of the lens within the box: 1 for the first lens, 2 + for the second lens, and so on. + • The focal length of the lens. + + At the end of the above example, the focusing power of each lens is as + follows: + + • rn: 1 (box 0) * 1 (first slot) * 1 (focal length) = 1 + • cm: 1 (box 0) * 2 (second slot) * 2 (focal length) = 4 + • ot: 4 (box 3) * 1 (first slot) * 7 (focal length) = 28 + • ab: 4 (box 3) * 2 (second slot) * 5 (focal length) = 40 + • pc: 4 (box 3) * 3 (third slot) * 6 (focal length) = 72 + + So, the above example ends up with a total focusing power of 145. + + With the help of an over-enthusiastic reindeer in a hard hat, follow the + initialization sequence. What is the focusing power of the resulting lens + configuration? + + Your puzzle answer was 229349. + + Both parts of this puzzle are complete! They provide two gold stars: ** + + At this point, you should [22]return to your Advent calendar and try + another puzzle. + + If you still want to see it, you can [23]get your puzzle input. + + You can also [Shareon [24]Twitter [25]Mastodon] this puzzle. + +References + + Visible links + 1. https://adventofcode.com/ + 2. https://adventofcode.com/2023/about + 3. https://adventofcode.com/2023/events + 4. https://teespring.com/stores/advent-of-code + 5. https://adventofcode.com/2023/settings + 6. https://adventofcode.com/2023/auth/logout + 7. Advent of Code Supporter + https://adventofcode.com/2023/support + 8. https://adventofcode.com/2023 + 9. https://adventofcode.com/2023 + 10. https://adventofcode.com/2023/support + 11. https://adventofcode.com/2023/sponsors + 12. https://adventofcode.com/2023/leaderboard + 13. https://adventofcode.com/2023/stats + 14. https://adventofcode.com/2023/sponsors + 15. https://www.honeycomb.io/product-overview + 16. https://en.wikipedia.org/wiki/Hard_hat + 17. https://adventofcode.com/2023/day/1 + 18. https://en.wikipedia.org/wiki/String_(computer_science) + 19. https://en.wikipedia.org/wiki/ASCII#Printable_characters + 20. https://en.wikipedia.org/wiki/Modulo + 21. https://en.wikipedia.org/wiki/Label_printer + 22. https://adventofcode.com/2023 + 23. https://adventofcode.com/2023/day/15/input + 24. https://twitter.com/intent/tweet?text=I%27ve+completed+%22Lens+Library%22+%2D+Day+15+%2D+Advent+of+Code+2023&url=https%3A%2F%2Fadventofcode%2Ecom%2F2023%2Fday%2F15&related=ericwastl&hashtags=AdventOfCode + 25. javascript:void(0); diff --git a/2023/day15/testinput b/2023/day15/testinput new file mode 100644 index 0000000..4f58f74 --- /dev/null +++ b/2023/day15/testinput @@ -0,0 +1 @@ +rn=1,cm-,qp=3,cm=2,qp-,pc=4,ot=9,ab=5,pc-,pc=6,ot=7