Advent of Code

--- Day 23: Coprocessor Conflagration ---

   You decide to head directly to the CPU and fix the printer from there. As
   you get close, you find an experimental coprocessor doing so much work that
   the local programs are afraid it will halt and catch fire. This would cause
   serious issues for the rest of the computer, so you head in and see what you
   can do.

   The code it's running seems to be a variant of the kind you saw recently on
   that tablet. The general functionality seems very similar, but some of the
   instructions are different:

     • set X Y sets register X to the value of Y.

     • sub X Y decreases register X by the value of Y.

     • mul X Y sets register X to the result of multiplying the value contained
       in register X by the value of Y.

     • jnz X Y jumps with an offset of the value of Y, but only if the value of
       X is not zero. (An offset of 2 skips the next instruction, an offset of -1
       jumps to the previous instruction, and so on.)

     Only the instructions listed above are used. The eight registers here,
     named a through h, all start at 0.

   The coprocessor is currently set to some kind of debug mode, which allows
   for testing, but prevents it from doing any meaningful work.

   If you run the program (your puzzle input), how many times is the mul
   instruction invoked?

   Your puzzle answer was 9409.

--- Part Two ---

   Now, it's time to fix the problem.

   The debug mode switch is wired directly to register a. You flip the switch,
   which makes register a now start at 1 when the program is executed.

   Immediately, the coprocessor begins to overheat. Whoever wrote this program
   obviously didn't choose a very efficient implementation. You'll need to
   optimize the program if it has any hope of completing before Santa needs
   that printer working.

   The coprocessor's ultimate goal is to determine the final value left in
   register h once the program completes. Technically, if it had that... it
   wouldn't even need to run the program.

   After setting register a to 1, if the program were to run to completion,
   what value would be left in register h?

   Your puzzle answer was 913.

   Both parts of this puzzle are complete! They provide two gold stars: **

   At this point, all that is left is for you to admire your advent calendar.

   If you still want to see it, you can get your puzzle input.

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